grep regex and variables

Asked Oct 19 '20 at 08:56

Active Oct 19 '20 at 17:09

Viewed 51 times

My issue is as follows:

This is the content of variable res:

% echo $res
large__noninteractive($|[[:blank:]])" | grep -E "(^|[[:blank:]])RAM.3000000($|[[:blank:]])" | grep -E "(^|[[:blank:]])CORES.1

And when I do as follows it gives me results (everything after grep -E "(^|[[:blank:]]) and before ($|[[:blank:]])" is the identical to the content of $res) :

cat queuedjobs | grep -E "(^|[[:blank:]])large__noninteractive($|[[:blank:]])" | grep -E "(^|[[:blank:]])RAM.3000000($|[[:blank:]])" | grep -E "(^|[[:blank:]])CORES.1($|[[:blank:]])"

but when I do:

cat queuedjobs | grep -E "(^|[[:blank:]])$res($|[[:blank:]])"

There are no results even though it is supposedly identical. I would appreciate any ideas for solving this issue.

I'm testing it in the command line but it will enter into a script.

I made the res as follows:

resource="large__noninteractive RAM.2500000 CORES.4"`
res=`echo $resource | sed "s/${queue}//g" | awk '{$1=$1};1' | sed 's/ /($|[[:blank:]])" \| grep -E "(^|[[:blank:]])/g'`

edited Oct 19 '20 at 17:09

muru

69,900
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asked Oct 19 '20 at 08:56

Jenny

You can't use the pipe `|` in a variable like that. Also, in your case I'd suggest using an array of patterns and something like https://unix.stackexchange.com/a/326270/70524 instead. – muru Oct 19 '20 at 09:06
Is `cat queuedjobs | grep -E "(^|[[:blank:]])$res($|[[:blank:]])"` a part of a Bash script or typed in the terminal? – Alexander Mashin Oct 19 '20 at 09:06
Is the `grep` commands actually part of the value `$res`? – Kusalananda Oct 19 '20 at 09:07
Bash script, and Yes, I inserted it like that: – Jenny Oct 19 '20 at 10:08

grep regex and variables

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