grep's name comes after the g/re/p ed command. Its primary purpose is to print the lines that match a regexp. It's not its role to edit the content of those lines. You have sed (the stream editor) or awk for that.
Now, some grep implementations, starting with GNU grep added a -o option to print the matched portion of each line (what is matched by the regexp, not its capture groups). You've got some grep implementation like GNU's again (with -P) or pcregrep that support PCREs for their regexps.
pcregrep actually added a -o<n> option to print the content of a capture group. So you could do:
pcregrep -o1 -o2 --om-separator=' ' '.zoo.(\d+).*:\s+(.*)'
But here, the obvious standard solution is to use sed:
sed -n 's/^.*\.zoo\.\([0-9]\{1,\}\).*:[[:space:]]\{1,\}/\1 /p'
Or if you want perl regexps, use perl:
perl -lne 'print "$1 $2" if /\.zoo\.(\d+).*:\s+(.*)/'
With GNU grep, if you don't mind the matches to appear on different lines, you can do:
$ grep -Po '\.zoo\.\K\d+|:\s+\K.*' < file
2
0.45654343
Note that while \K resets the start of the matched portion, that doesn't mean you can get away with the two parts of the alternation overlapping.
grep -Po '.zoo.(\K\d+|.: \K.)'
would not work, just like echo foobar | grep -Po 'foo|foob' wouldn't work (at printing both foo and foob). foo|foob first matches foo and then grep looks for potential other matches in the input after the foo, so starting at the b of bar, so can't find any more after that.
Above with grep -Po '\.zoo\.\K\d+|:\s+\K.*', we only look for :<spaces><anything> in the second part of the alternation. That does match in the part that is after .zoo.<digits> but that also means it would find those :<spaces><anything> anywhere in the input, not only when they follow .zoo.<digits>.
There is a way to work around that though, using another PCRE special operator: \G. \G matches at the start of the subject. For a single match, that's equivalent to ^, but with multiple matches (think of sed/perl's g flag in s/.../.../g) like with -o where grep tries to find all the matches in the line, that also matches after the end of the previous match. So if you make it:
grep -Po '\.zoo\.\K\d+|(?!^)\G.*:\s+\K.*'
Where (?!^) is a negative look-ahead operator that means not at the beginning of the line, that \G will only match after a previous successful (non-empty) match, so .*:\s+\K.* will only match if it follows a previous successful match, and that can only be the .foo.<digits> one since the other part of the alternation matches til the end of the line.
On an input like:
.zoo.1.zoo.2 tar: blah
That would output:
1
2
blah
Though. If you did not want that, you'd also want the first part of the alternation to only match at the beginning of the line. Something like
grep -Po '^.*?\.zoo\.\K\d+|(?!^)\G.*:\s+\K.*'
That still outputs 2 on an input like .zoo.2 no colon character or .zoo.2 blah:. Which you could work around with a look-ahead operator in the first part of the alternation, and look for at least one non-space after :<spaces> (and also using $ to avoid issues with non-characters)
grep -Po '^.*?\.zoo\.\K\d+(?=.*:\s+\S.*$)|(?!^)\G.*:\s+\K\S.*$'
You'd probably need a few pages of comments to explain that regexp, so I would still go for the straightfoward sed/perl solutions...
