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I have a sample file below:

# This is a test file. This is a test file. This is a test file  
This is a test file. This is a test file. This is a test file.  
This is a test file.

# Need to output just this paragraph.Need to output just this paragraph.  
Need to output just this paragraph TOO. Need to output just this paragraph.  
Need to output just this paragraph.

I need to output just the second paragraph starting from "#" till the last sentence in the paragraph.

How do I grep and output based on the pattern? Say if the file has more paragraphs, and I would like to output the paragraph which contains the word "TOO".

Rui F Ribeiro
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Johan Hakim Fahmi
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2 Answers2

2

If the paragraphs are empty line separated:

awk -v RS= -v ORS='\n\n' /TOO/

An empty record separator (RS) means paragraph mode where records are separated by sequences of empty lines.

If they are # separated:

awk -v RS='#' '/TOO/ {print RS $0}'

or

pcregrep -Mo '#[^#]*?TOO[^#]*'
  • -M for multiline grep
  • -o to output the matched portion only
Stéphane Chazelas
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perl -00ne 'print if /TOO/'
  • -00 means paragraph mode (records are separated by one or more empty lines).
JJoao
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