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What is the most elegant way to make this work?

prc_count=$(nproc --all)
factor=0.5
prc_count=$((prc_count*factor))

I tried with awk/echo and no success

Stat.Enthus
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    If you're just multiplying by a constant factor like `0.5`, you could do `$(( a * 5 / 10 ))`. Also, if you're going to say "I tried xyz and no success", it's better to show what exactly you tried and what exactly the problem was, it makes it easier to help you. – ilkkachu Jun 08 '22 at 12:20
  • Thanks, the idea that factor can be modified from 0.5 to 2.5 or 3 – Stat.Enthus Jun 08 '22 at 12:33

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