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I am using Linux and I want to create a list of files stored in folder and sub-folders with the filenames and their absolute locations concatenated as one string e.g. (/A/B/C/file.ext) some modification of:

ls -lR $PWD/* | awk '{printf(" %s/%s\n", ENVIRON["PWD"], $9); }'

to produce output where the PWD "current location" is replaced with the files absolute path.

αғsнιη
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A.Abousetta
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2 Answers2

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Just use find.

find $(pwd) -type f -not -path '*/\.*'

This lists all the files in the cwd with their full paths

Alex
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    Why the `-not` part? This would exclude hidden files, which wasn't stated by the OP. – bxm Jan 04 '22 at 12:31
  • because they did not state that there should be absolute file paths with . , and that may cause some more trouble for OP – Alex Jan 04 '22 at 12:33
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    More to the point, @bxm, the command used by the OP will exclude hidden files, so it is reasonable to provide alternatives that would produce the same output. – terdon Jan 04 '22 at 12:39
  • [Quote right](https://unix.stackexchange.com/a/131767/108618). – Kamil Maciorowski Jan 04 '22 at 13:48
  • That assumes that the current working directory doesn't contain space, tab, newline or wildcard characters and is not hidden itself. With some `find` implementations, that can fail to exclude hidden files / dirs whose name is encoded in a charset different from that of the current locale. Note that it still descends into hidden dirs even if it excludes all files in there for output. – Stéphane Chazelas Jan 04 '22 at 15:07
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With zsh:

print -rC1 ~0/**/*(ND)

Would print raw on 1 Column the paths of all non hidden files in ~0 (same as $PWD) sorted lexically. You could do the same with GNU find and sort with:

LC_ALL=C find "$PWD" -mindepth 1 -name '.*' -prune -o -print0 |
  sort -z |
  tr '\0' '\n'

That assumes however that the base name of $PWD does not start with ..

On FreeBSD, you'd be able to do:

find "$PWD" -depth +0 '(' -name '.*' -prune -o -print0 ')' |
  sort -z |
  tr '\0' '\n'
Stéphane Chazelas
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