Why the following bash snippet is not working?

Question

This question is related to Bash. The following is working in terminal:

url="http://user:[email protected]:80/"
echo $url | sed -e 's/[^/]*\/\/\([^@]*@\)\?\([^:/]*\).*/\2/'

Terminal output: example.com

How to fix the following?

domain=$($url | sed -e 's/[^/]*\/\/\([^@]*@\)\?\([^:/]*\).*/\2/') # not working
echo $domain

you forgot `echo` in `domain=$(echo "$url" | ...)`; and please do not duplicate your question of https://unix.stackexchange.com/q/624145/72456 — αғsнιη, Dec 12 '20 at 19:32
@ αғsнιη THX. That works: domain=$(echo "$url" | sed -e 's/[^/]*\/\/$[^@]*@$\?$[^:/]*$.*/\2/'); echo $domain — Alfred.37, Dec 12 '20 at 20:46
@ roaima THX. I checked the linked source before submitting my question. A I didnt successfull tu adapt the solution from follow, for my question: https://unix.stackexchange.com/questions/16024/how-can-i-assign-the-output-of-a-command-to-a-shell-variable — Alfred.37, Dec 12 '20 at 20:49

score 0 · Accepted Answer · answered Dec 12 '20 at 19:28

0

The left side of the pipe has to be a valid shell command that produces output to stdout. In bash you can also use <<< like that:

domain=$(sed -e 's/[^/]*\/\/\([^@]*@\)\?\([^:/]*\).*/\2/' <<< "$url")

answered Dec 12 '20 at 19:28

1 Answers1