You could parse the output of ip address: Mine looks like this (I've added extra IP addresses to show it can be done):
$ ip address
1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN group default qlen 1000
link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00
inet 127.0.0.1/8 scope host lo
valid_lft forever preferred_lft forever
inet6 ::1/128 scope host
valid_lft forever preferred_lft forever
2: enp10s0: <NO-CARRIER,BROADCAST,MULTICAST,UP> mtu 1500 qdisc mq state DOWN group default qlen 1000
link/ether f0:79:59:dc:c4:bf brd ff:ff:ff:ff:ff:ff
3: eno1: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UP group default qlen 1000
link/ether f0:79:59:dc:c3:75 brd ff:ff:ff:ff:ff:ff
altname enp0s25
inet 192.168.1.100/24 brd 192.168.1.255 scope global noprefixroute eno1
valid_lft forever preferred_lft forever
inet 129.168.1.101/24 scope global eno1
valid_lft forever preferred_lft forever
inet6 fe80::f279:59ff:fedc:c375/64 scope link noprefixroute
valid_lft forever preferred_lft forever
If we grep a regex for the address we could end up with a list of IPv4 addresses.
$ IPV4=$(ip address | grep -oE '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\/[0-9]{1,2}' )
$ echo $IPV4
127.0.0.1/8 192.168.1.100/24 129.168.1.101/24
$ for i in $IPV4; do echo $i; done
127.0.0.1/8
192.168.1.100/24
129.168.1.101/24
You'd just need to write a regex for IPv6 (if desired) and MAC to round it out.