execute all files under a directory

Asked Sep 29 '20 at 03:19

Active Sep 29 '20 at 03:19

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Im trying to use find to execute all the files under a directory. I have a sed script that will replace all # with //.
assume my directory is /path/to/directory and it contains file1 file2 file3

using find and sed: find /path/to/directory -type f -exec sed -f file.sed {} \;.

how do I make it to where it runs ALL files (file1 file2 file3) under the path/to/directory directory?

asked Sep 29 '20 at 03:19

bull

1

What is the error you are getting? Merely saying its not working is very unhelpful. – Rakesh Sharma Sep 29 '20 at 05:11
it says no directory or file found – bull Sep 29 '20 at 06:00
4

Does this answer your question? [Execute sed on all file under a directory](https://unix.stackexchange.com/questions/611930/execute-sed-on-all-file-under-a-directory) – G-Man Says 'Reinstate Monica' Sep 29 '20 at 06:44
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`-exec` is executed from the starting directory, while `-execdir` is used to execute commands in the directory where the matching file is found. See `man find`. Or do you want a third directory to be specified? – FelixJN Sep 29 '20 at 10:30
Are the files that you are `find`ing, executable-files / programs? – ctrl-alt-delor Oct 09 '20 at 16:50

execute all files under a directory

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