How can I assign an initial/default password to a user in Linux?

Question

I found a guide that explains how to set a user's password. I'm trying to automate it and send an e-mail to the user like:

userid created with password XYZ.
request to change the initial password.

According to the doc above, an encrypted password needs to be created using Python and fed to the usermod command like this:

 usermod -p "<encrypted-password>" <username>

Are there any other simpler ways to do this? I don't want to download any special utility to do it; it should be generalized as much as possible.

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Edit: Even the method given in the above link doesn't seem to work for me:

bash-3.00# python
Python 2.4.6 (#1, Dec 13 2009, 23:43:51) [C] on sunos5
Type "help", "copyright", "credits" or "license" for more information.
>>> import crypt; print crypt.crypt("<password>","<salt>")
<sOMrcxm7pCPI
>>> ^D
bash-3.00# useradd -g other -p "sOMrcxm7pCPI" -G bin,sys -m -s /usr/bin/bash mukesh2
UX: useradd: ERROR: project sOMrcxm7pCPI does not exist.  Choose another.
UX: useradd: sOMrcxm7pCPI name should be all lower case or numeric.

Answer 1

You can use chpasswd to do it, like this:

echo "username:newpassword" | chpasswd

You can pipe into chpasswd from programs other than echo, if convenient, but this will do the trick.

Edit: To generate the password within the shell script and then set it, you can do something like this:

# Change username to the correct user:
USR=username
# This will generate a random, 8-character password:
PASS=`tr -dc A-Za-z0-9_ < /dev/urandom | head -c8`
# This will actually set the password:
echo "$USR:$PASS" | chpasswd

For more information on chpasswd, see http://linux.die.net/man/8/chpasswd

(Command to generate password was from http://nixcraft.com/shell-scripting/13454-command-generate-random-password-string.html)

Answer 2

You can use OpenSSL to generate the random password (16 characters, in this case):

# 1000 bytes should be enough to give us 16 alphanumeric ones
p=$(openssl rand 1000 | strings | grep -io [[:alnum:]] | head -n 16 | tr -d '\n')

Then feed the hashed password to useradd or usermod

# omit the "-1" if you want traditional crypt()
usermod -p $(openssl passwd -1 "$p") <username>

EDIT:

Since posting this in 2012, newer versions of OpenSSL have added functionality to the openssl passwd command. Instead of using the -1 option to get an MD5-based hash, modern versions also support -5 for SHA256-based hashes and -6 for SHA512-based hashes.

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Credit where due: The password generation is adapted from a similar method that uses /dev/urandom instead of openssl.

Answer 3

useradd should work (I've done it on Ubuntu). Maybe check that each of your args are correct (thee groups exist, the path is right to bash). You can run the command with just a password and user, and then use userdel to remove and then retry with more parameters, to see what one causes the issue (brute force approach).

There is also newusers (see the man page), at least under Ubuntu, where you give it a file with passwd file like info, including plain text passwords and it will create those users. Nice way to do many users at once.

Answer 4

simplest way I found :

PASSWD="mySeCr3t-default-pa55" 
echo ${PASSWD} | passwd --stdin username_here

Answer 5

I worked as follows and tried the following: Create a text file (e.g. myfile.txt) with 2 lines, each line contains the default password.

then run:

cat myfile.txt | sudo passwd <username>

I tried it and it works for ubuntu!