what is the meaning of %< in printf statement?

Question

i get </ttd> instead of </td> in the below printf. Can someone please explain why. i want % symbol in my output. But it adds extrac t in my output.

awk '{printf("<td>%0.2f`%</td>`\n",$0)}'

bash-4.3$ echo "50" | awk '{printf("<td>%0.2f</td>\n",$0)}'
<td>50.00</td>
bash-4.3$
bash-4.3$ echo "50" | awk '{printf("<td>%0.2f%</td>\n",$0)}'
<td>50.00%</ttd>
bash-4.3$

thanks. it works.. please add this answer.. i will accept it — Kamaraj, Jun 25 '19 at 09:24
The dupe is not an _exact_ duplicate, but the issue and the solution is the same. It's either that or closing it as "off-topic (typo)". — Kusalananda, Jun 25 '19 at 09:28

score 4 · Answer 1 · answered Jun 25 '19 at 09:27

4

I can't find any reference of %< neither in man 1 printf nor man 3 sprintf (man awk refer to sprintf), however :

In almost every implementation of printf (C,awk,php,...) one is to use %% to print a single % sign.

answered Jun 25 '19 at 09:27

Archemar

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There's nothing in [format control letters](https://www.gnu.org/software/gawk/manual/gawk.html#Control-Letters) or modifiers in the GNU awk manual, either. – muru Jun 25 '19 at 09:28

what is the meaning of %< in printf statement?

1 Answers1