I have a folder with 20000 files in it. I need to split it into subfolders with increasing directory name (dir_1, dir_2....) with each folder having 500 files each in such a way that for example if files are from file_1.png to file_20000, the first folder should contain first 500 files i.e., file_1 to file 500 and immediate folder should contain files in a continued manner i.e, file_501 to file_1000 and so on.

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Rui F Ribeiro
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Praveen Kumar
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5please _please_ do not post images of text. Or, if you must, at least don't post such sparse images, and make them more helpful in the context of the question. – DopeGhoti Jan 07 '19 at 18:15
3 Answers
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#!/bin/sh
files_per_dir=500
set -- file_*
printf 'There are %d files\n' "$#"
printf 'Putting %d files in each new directory\n' "$files_per_dir"
N=0 # directory counter
n=0 # file counter
for filename do
if [ "$(( n % files_per_dir ))" -eq 0 ]; then
N=$(( N + 1 ))
dir="dir_$N"
printf 'Creating directory %s\n' "$dir"
# mkdir "$dir"
fi
n=$(( n + 1 ))
printf 'Moving %s to %s\n' "$filename" "$dir"
# mv -i -- "$filename" "$dir"
done
The above would put 500 files into each directory (the actual commands that changes things have been commented out for safety). The filenames are assumed to match file_* and each new directory will be called dir_N where N is a positive integer.
If you want to move the files based on their numerical names (the above sorts the files in lexicographical order), then use
printf 'Moving %s to %s\n' "file_$n" "$dir"
# mv -i -- "file_$n" "$dir"
instead (i.e. replace the corresponding two lines in the first script with these, in this order).
Shortened version:
#!/bin/sh
files_per_dir=500
set -- file_*
n=0
for filename do
n=$(( n + 1 ))
N=$(( (n/files_per_dir) + 1 ))
[ ! -d "dir_$N" ] && mkdir "dir_$N"
# mv -i -- "$filename" "dir_$N"
# or...
# mv -i -- "file_$n" "dir_$N"
done
Kusalananda
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0
cd lotsafiles
for i in {1..20000}; do
dirnum="$(((i/500)+1))"
mkdir -p "dir_${dirnum}" # using -p allows this to be less noisy on repeat runs
mv "file${i}.png" "dir_${dirnum}"/
done
DopeGhoti
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Something simple along the lines of:
#!/bin/bash
typeset -i i
typeset -i j
typeset -i k
i=0
j=0
k=0
mkdir dir_$j
for file in * ; do
i=$i+1
k=$k+1
if [ $i = 500 ] ; then
j=$j+1
i=0
mkdir dir_$j
fi
mv "$file" dir_$j/file_$k
done
Not tested, so you might put an echo in front of the mv "$file" dir_$j to see if it does what you want. Anyway it will give you an idea of how to do what you want.
Ljm Dullaart
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Yes it works. That's why the `typeset -i` is there. Yes, I use string comparison, but that also works. Would you prefer I put `#!/bin/sh` as first line? – Ljm Dullaart Jan 07 '19 at 18:23
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1Using the string comparison operator for `test` (`=`) for numerical comparisons is bad practice. Use the numerical comparisons (`-eq`) when performing numerical equality tests. Using the wildard (`for file in *`) may catch more files than the specified `file_{1..20000}.png`. – DopeGhoti Jan 07 '19 at 18:32