Counting the number of lines between same repeating pattern

Question

I have refer this Grep the lines between the occurrence of the same pattern , I don't want to split into file; instead, I want to store it into an array. File count.txt contain:

My script code is:

total=$(sed -n \$= count.txt)
c=0
k=0
lineno=0
var="0"
for i in $(cat count.txt);
do
        if ["$i" -eq "$var"]
        then
                arr[$((k++))]=c
                c=0
                c=$((c+1))

        else
                c=$((c+1))
                if ["$lineno" -eq "$total"]
                then
                        arr[$((k++))]=c
                fi
        fi
        lineno=$((lineno+1))
done

The above logic is tested on C++ launguage which on printing the array shows : 0 4 3 2 Firstly, my script is showing error like line 9: [0: command not found. Secondly, is there any efficient method to store the repeated count in array, like above output?

The `command not found` error is because your `[` test lacks the required whitespace: `[ "$i" -eq "$var" ]` — steeldriver, Dec 27 '18 at 13:06
There is not output instruction; in addition `=c` is putting the letter c in the variable, may be you want `=$c` and the first test is right the first time as `0=0` this explains the potential output 0 in sequence instead of `4 3 2`. — matzeri, Dec 27 '18 at 14:22

score 1 · Answer 1 · answered Dec 27 '18 at 15:07

1

An awk one-liner:

awk -v patt="0" -v prev=1 '
    $0 ~ patt {print NR - prev; prev = NR} 
    END {print NR + 1 - prev}
' file

answered Dec 27 '18 at 15:07

glenn jackman

84,176
15
116
168

score 0 · Answer 2 · answered Dec 27 '18 at 14:13

Try this,

LINES=(`cat count.txt `)
arr=()
arrIndex=0
a=`echo $LINES`
for i in "${!LINES[@]}"; do
if [[ "${LINES[$i]}" = "$a" ]]; then
        arr[arrIndex]=`echo "${i}"`
        arrIndex=$((arrIndex+1))
fi
done
arr[arrIndex]=`echo ${#LINES[@]}`
arrOut=()
for ((i=1; i<"${#arr[@]}"; ++i))
do
        j=`expr $i - 1 `
        arrOut[$i]=`echo "${arr[$i]} ${arr[$j]}" | awk '{a=$1-$2;print a}'`
done

echo ${arrOut[@]}

Counting the number of lines between same repeating pattern

2 Answers2