Sed command writes the expression in outer ifmodule

Question

my config file has this

<IfModule mod_dir.c>
    DirectoryIndex index.html index.cgi index.pl index.php index.xhtml index.htm
</IfModule>

I want to change index.php to index.temp

I created this

sed -i -e '/s/index.php/index.temp/‘ dir.conf

It makes this,

<IfModule mod_dir.c>
    DirectoryIndex index.html index.cgi index.pl index.php index.xhtml index.htm
</IfModule>
ndex.php/index.temp/

You presumably want to use the `s` substitute command, so do not begin with `/` as `/s/` means match the pattern `s`, and then the command is `i` which inserts the rest of the line. So use `sed -i -e 's/index.php/index.temp/'` — meuh, Nov 03 '18 at 20:06

score 0 · Answer 1 · answered Dec 16 '20 at 08:03

Your s/// command is prefixed by a / which would make sed misunderstand it. It also looks as if the terminating single quote is not an ordinary single quote (‘ instead of '), but that may be an issue in just this question.

To change all instances of the string index.php to index.temp in some file dir.conf, use

sed -i 's/index\.php/index.temp/g' dir.conf

The dot in the pattern needs to be escaped as it is special in regular expressions (you could also have used [.] in place of \.). Also note that this is using -i for "in-place editing", which is not generally portable.

To make sure that you don't change myindex.php into myindex.temp or index.php3 into index.temp3, use \< and \> (or \b in place of both) to match the word boundaries:

sed -i 's/\<index\.php\>/index.temp/g' dir.conf

Sed command writes the expression in outer ifmodule

1 Answers1