Extract value from XML file using shell script

Question

I have file filestore.xml from which I need to extract /local/armdata/data/filestore1, /local/armdata/data/filestore2.

grep binariesDir filestore.xml
    <binariesDir>/local/armdata/data/filestore1</binariesDir>
    <binariesDir>/local/armdata/data/filestore2</binariesDir>

Is there any way to do this?

grep binariesDir filestore.xml /local/armdata/data/filestore1 /local/armdata/data/filestore2 — rajesh, Oct 23 '18 at 06:20
Please don't add information in the comments, edit the question, especially if it needs formatting. — RalfFriedl, Oct 23 '18 at 06:37

pLumo · Answer 1 · 2018-10-23T09:05:39.627

2

Using XMLStarlet:

xml sel -t -v '//binariesDir' filestore.xml

on Ubuntu with xmlstarlet package installed, I need to use this:

xmlstarlet sel -t -v '//binariesDir' filestore.xml

edited Oct 23 '18 at 09:05

answered Oct 23 '18 at 09:00

pLumo

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score 1 · Answer 2 · answered Oct 23 '18 at 06:42

1

You can use sed.

sed -nre 's:^.*<binariesDir>(.*)</binariesDir>.*$:\1:p' filestore.xml

This handles both the searching for binariesDir and extracting the value between <binariesDir> and </binariesDir>.

answered Oct 23 '18 at 06:42

RalfFriedl

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Extract value from XML file using shell script

2 Answers2