Dropping filename extensions with find -exec

Question

When using find, how can I drop the original filename extension (i.e. .pdf) from the second pair of -exec braces ({})?

For example:

find ~/Documents -regex 'LOGIC.*\.pdf' -exec pdf2svg {} {}.svg \;

Input filename:

~/Documents/LOGIC-P_OR_Q.pdf

Output filename:

~/Documents/LOGIC-P_OR_Q.pdf.svg

Desired filename:

~/Documents/LOGIC-P_OR_Q.svg

It would be better to use `-name "LOGIC*.pdf"` to match the filename as `-regex` matches against the full pathname. — Kusalananda, Jun 29 '18 at 13:00

steeldriver · Accepted Answer · 2018-06-29T12:52:22.217

9

You can use an "in-line" shell script, and parameter expansion:

-exec sh -c 'pdf2svg "$1" "${1%.pdf}.svg"' sh {} \;

or (more efficiently, if your find supports it)

-exec sh -c 'for f; do pdf2svg "$f" "${f%.pdf}.svg"; done' sh {} +

edited Jun 29 '18 at 12:52

answered Jun 29 '18 at 12:49

steeldriver

`-exec ... {} +` is standard syntax, so it _ought_ to be supported. – Kusalananda Aug 24 '21 at 19:51

score -1 · Answer 2 · answered Jun 29 '18 at 13:01

-1

One method would be to run the results through a basic script -

for i in $( find ~/Documents -regex 'LOGIC.*\.pdf' )  
do  
    o=$( echo $i | sed -e s/.pdf$// )  
    pdf2svg $i ${o}.svg  
done

answered Jun 29 '18 at 13:01

StuWhitby

1

https://unix.stackexchange.com/questions/321697 – Kusalananda Jun 29 '18 at 13:03

2 Answers2