How to print list filename using ls, but if not found retrun empty string?

Question

I have name file

hua.txt
hai.txt

if

print ls *{hua,las}* > taka.txt

in taka.txt return

ls hua.txt *las*

i want to *las* not there,

i just want in taka.txt

ls hua.txt

and filter *{hua,las}* must there... too

please help

For `bash` and `zsh` there is `shopt -s nullglob`, but see [this answer](http://unix.stackexchange.com/a/204944) for an in-depth discussion. — Satō Katsura, Oct 10 '16 at 04:54

score 3 · Answer 1 · answered Oct 10 '16 at 06:57

Many shells have different handles when a pathname expansion (glob) fails to match anything.

For example, in bash you have two shell options:

nullglob:

If a glob pattern fails to match anything, it is treated literally by default in bash. You can disable this behavior to return an empty string by setting the nullglob option beforehand:
```
shopt -s nullglob
```
failglob:

This is more explicit, when a glob pattern fails to match anything bash shows a relevant error message:
```
shopt -s failglob
```

Given your circumstances, you should go with nullglob if you are using bash, or look out for any similar option if you are using a different shell.

How to print list filename using ls, but if not found retrun empty string?

1 Answers1