Sox: Convert a .wav file with required properties in a single command

Question

I have a test.wav file. I need to use this file to process an application, with following properties:

monochannel
16 kHz sample rate
16-bit

Now, I'm using the following commands to attain these properties:

sox disturbence.wav -r 16000 disturbence_16000.wav
sox disturbence_16000.wav -c 1 disturbence_1600_mono.wav
sox disturbence_1600_mono.wav -s -b 16 disturbence_1600_mono_16bit.wav

Here to get a single file, three steps are involved and two temporary files are created. It is a time-consuming process.

I thought of writing a script to do these process but I'm keeping this is a last option.

In single command, can I convert a .wav file to the required format?

What should the `-s`-option do? – Golar Ramblar Apr 04 '16 at 08:43 — Golar Ramblar, Apr 04 '16 at 08:43

score 23 · Accepted Answer · answered Apr 04 '16 at 08:43

23

sox disturbence.wav -r 16000 -c 1 -b 16 disturbence_16000_mono_16bit.wav

gives within one command

Sample rate of 16 kHz (-r 16000),
one channel (mono) (-c 1),
16 bits bit depth (-b 16).

answered Apr 04 '16 at 08:43

Golar Ramblar

1,771
1
18
28

ash17 · Answer 2 · 2021-12-28T13:24:06.697

1

one-liner for all .wav files in the directory:

for file in *.wav; do sox $file -r 16000 -c 1 -b 16 "$(basename $file .wav)_16000_mono_16bit.wav" -V; done

edited Dec 28 '21 at 13:24

answered Dec 27 '21 at 15:30

ash17

11
2

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Sox: Convert a .wav file with required properties in a single command

2 Answers2