0

I want to make some notification to user every day at the same time:

any_hour:50

And I wrote to crontab -e:

50 * * * * DISPLAY=:0 /usr/bin/notify-send -i /home/nazar/Pictures/icons/download_manager.png "Break" "Make a break for 10 min"

When I run it from console:

notify-send -i /home/nazar/Pictures/icons/download_manager.png "Break" "Make a break for 10 min"

I have desired result:

enter image description here

But when I working at PC I don't have this output at desired time.

Any suggestion?

UPDATE:

I updated cron job to:

50 * * * * DISPLAY=:0 /usr/bin/notify-send -i /home/nazar/Pictures/icons/download_manager.png "Work Break" "Make a break for 10 min, please!" 2>&1 | tee -a cron.out

After executing it file was created but it is empty.

I tried to update my cron job as follows:

00 13 * * *  /home/nazar/Documents/scripts/lunch_break_job.sh
50 *  * * *  /home/nazar/Documents/scripts/pc_break.sh

# just cron test
*/1  *  * * *  /home/nazar/Documents/scripts/cron_job_test.sh

and cron_job_test.sh looks:

#!/bin/bash

export DISPLAY=0.0
export XAUTHORITY=/home/matrix/.Xauthority

if [ -r "$HOME/.dbus/Xdbus" ]; then
  . "$HOME/.dbus/Xdbus"
fi

/usr/bin/notify-send "hello"

when I run this script from terminal:

./cron_job_test.sh

I get notification correctly.
But crontab doesn't run this script every minute.

Why does this happen?
And how to resolve execution of this cron job?

catch23
  • 219
  • 2
  • 6
  • 15
  • 1
    This is probably because setting DISPLAY isn't enough; your X server must be rejecting the connection. Are you able to receive error output from cron jobs (it sends e-mail)? That would allow use to better understand what is going on. Otherwise, append `2>&1 | tee -a cron.out` to your job to create a log file. – dhag Dec 04 '15 at 16:53
  • @dhag can you explain more about logging cron? have should look my updated cron job? – catch23 Dec 04 '15 at 17:16
  • As I said, add `2>&1 | tee -a cron.out` to the end of your cron job, and, after it runs, look in file `cron.out`. – dhag Dec 04 '15 at 18:02
  • @dhag I updated question. – catch23 Dec 04 '15 at 19:54
  • The `cron_job_test.sh` you pasted is missing the closing `"` (last line). Is this just a copy & paste error? (Please [edit] your question and fix it if so.) – derobert Dec 04 '15 at 21:14
  • @derobert it is just copy/paste trouble. script works fine. – catch23 Dec 04 '15 at 22:20

1 Answers1

1

You probably need to edit the crontab of that particular user i.e. 

su -l nazar
crontab -e
user3861788
  • 141
  • 2
  • can you explain more? I didn't get what your answer means. – catch23 Dec 04 '15 at 16:43
  • 2
    That would only be useful if we had reason to believe the asker is running commands as root, which seems to me an unreasonable assumption. – dhag Dec 04 '15 at 16:46
  • @dhag Do you mean to run `sudo crontab -e`? – catch23 Dec 04 '15 at 16:47
  • 1
    No, I mean that this answer seems completely irrelevant to your problem. – dhag Dec 04 '15 at 16:50
  • Well he refers to "the user", unless he is referring to himself in the third person it's perfectly logical to assume that he *might* be trying to edit his own crontab given that he makes no mention of running it under a another user. But thinking about it, shouldn't his above syntax be: 50 * * * * export DISPLAY=:0 && /usr/bin/notify-send -i /home/nazar/Pictures/icons/download_manager.png "Break" "Make a break for 10 min" – user3861788 Dec 04 '15 at 16:58
  • @dcrdev do you mean add `&&`? – catch23 Dec 04 '15 at 17:13
  • I see where your assumption comes from, @dcrdev, that makes some sense. The `VAR=value command` form should be valid syntax. – dhag Dec 04 '15 at 18:01