Head and tail command

Question

How can i do this exercise in unix? Create the following command: lshead.bash – list the first few lines of every file in a directory specified by the argument. This command should also allow options to either list the first n lines or the last n lines of the files. Example command: lshead.bash –head 10 documents would list the first ten lines in every file in the documents directory.

Answer 1

This code gives the basic idea. You can add some features on your own, if want

EDIT

#!/bin/bash
cur_dir=`pwd`
function head_file()
{
    ls -p $cur_dir | grep -v / | while read file;do
        echo "First $1 lines of the FILE: $file"
        cat $file | head -n+$1 # Displaying the First n lines
        echo "*****************END OF THE FILE: $file**************"
    done
}

function tail_file()
{
    ls -p $cur_dir | grep -v / | while read file;do
        echo "Last $1 lines of the FILE: $file"
        cat $file | tail -n+$1 # Displaying the last n lines
        echo "**************END OF THE FILE: $file******************"
    done
}


case "$1" in
  head)
        head_file $2
        ;;
  tail)
        tail_file $2
        ;;

    *)
        echo "Invalid Option :-("
        exit 1
esac
exit 0