Because of specifics of my archiving needs I am not comfortable with solid tar.gz archives and use 7z instead.
I use the following command to do this:
7z a -t7z -m0=lzma -mx=9 -mfb=64 -md=32m -ms=off ~/my/folder.7z ~/my/folder/*
To create an archive of everything inside ~/my/folder/ as the ~/my/folder.7z file.
But ~/my/folder/.hiddenFolder doesm't get into the archive then. How to fix this? Isn't * supposed to return all the files and folders?
7z a -t7z -m0=lzma -mx=9 -mfb=64 -md=32m -ms=off ~/my/folder.7z ~/my/folder/.
Example directory structure
test1
├── .hidden
└── normal.txt
0 directories, 2 files
Try following commands
Root folder with all its contents.
7za a test1_a.7z ~/test1/
gives
Date Time Attr Size Compressed Name
------------------- ----- ------------ ------------ ------------------------
2017-08-06 09:23:51 D.... 0 0 test1
2017-08-06 09:23:44 ....A 0 0 test1/.hidden
2017-08-06 09:23:51 ....A 0 0 test1/normal.txt
------------------- ----- ------------ ------------ ------------------------
2017-08-06 09:23:51 0 0 2 files, 1 folders
No root folder and no hidden files
7za a test1_b.7z ~/test1/*
gives
Date Time Attr Size Compressed Name
------------------- ----- ------------ ------------ ------------------------
2017-08-06 09:23:51 ....A 0 0 normal.txt
------------------- ----- ------------ ------------ ------------------------
2017-08-06 09:23:51 0 0 1 files
No root folder but hidden files are included (it's what we usually want)
7za a test1_c.7z ~/test1/.
gives
Date Time Attr Size Compressed Name
------------------- ----- ------------ ------------ ------------------------
2017-08-06 09:23:44 ....A 0 0 .hidden
2017-08-06 09:23:51 ....A 0 0 normal.txt
------------------- ----- ------------ ------------ ------------------------
2017-08-06 09:23:51 0 0 2 files
If you want the contents of a single directory, an easy method is to change to it first:
cd ~/my/folder
7z a -t7z -m0=lzma -mx=9 -mfb=64 -md=32m -ms=off ~/my/folder.7z .
What you saw is that * expands to the list of names of files that don't begin with a .. That's the documented behavior, and it's the main reason why files whose name begins with a . are said to be hidden (the other is that ls doesn't show them by default).
There's no really convenient portable way to list all files in a directory. You can use
~/my/folder/..?* ~/my/folder/.[!.]* ~/my/folder/*
but if there is no file matching one of the patterns then the pattern will remain unexpanded. In bash, you can set the dotglob option to avoid treating a leading . specially (. and .. are still excluded from the matches):
shopt -s dotglob
7z a -t7z -m0=lzma -mx=9 -mfb=64 -md=32m -ms=off ~/my/folder.7z ~/my/folder/*
In ksh, or in bash if you set the extglob option (or in zsh if you set the ksh_glob option), you can write a pattern that matches all files except . and ..:
7z a -t7z -m0=lzma -mx=9 -mfb=64 -md=32m -ms=off ~/my/folder.7z ~/my/folder/@(..?*|.[!.]*|*)
In zsh, there's a simpler way of saying that . must not be treated specially in a pattern:
7z a -t7z -m0=lzma -mx=9 -mfb=64 -md=32m -ms=off ~/my/folder.7z ~/my/folder/*(D)
No, * is not supposed to return all files. It returns only visible ones.
The easier solution is:
cd ~/my/folder
7z a -t7z -m0=lzma -mx=9 -mfb=64 -md=32m -ms=off ~/my/folder.7z .
I extracted my zip archives using 7z (in Linux), I have a folder full of zips.
I have used:
7z x *.zip -o* to extract the zip files
I need to figure out: 7z a {folders from above command} -r
Keeping the above in mind, I want to use the 7z a command to create a 7z archive, but using the folder name that was created in the extraction part. How can that be done?
