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I have a directory with a very large number of subdirectories (~800) that were generated programmatically. I want to get a count of the number of files in each of these subdirectories to check for anomalies (if the code broke on a run then some of the files will be missing). What's a quick way to do this? The sort of output I'm looking for is: 

Name_of_Folder_1 [# of files in Folder 1]   
Name_of_Folder_2 [# of files in Folder 2]
...
mikefallopian
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    It's rarely used, but `diff` will happily report the differences between folders. `diff folder1 folder2`. – steve Aug 12 '15 at 20:30
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    See also [How can I get a count of files in a directory using the command line?](http://unix.stackexchange.com/q/1125) and there are more related questions if you take the time to search the site. – don_crissti Aug 12 '15 at 20:41

2 Answers2

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This will get you the count of files in each subdirectory of the current directory, dealing with any strange file names (with gnu find). 

find . -maxdepth 2 -mindepth 2 -type f -printf "%h\0" | uniq -zc | tr '\0' '\n'
Matt
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Assuming that you have no spaces in your directory names:

for dir in $(find . -type d); do
    echo "${dir}: $(find ${dir} -maxdepth 1 -type f | wc -l)"
done
Andy Dalton
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