I have this command where I want to filter make output:
cd /app && make && sudo nginx -g 'daemon off;'
What is the correct way to insert make | pv -q -L 100 here?
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Gilles 'SO- stop being evil'
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anatoly techtonik
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possible duplicate of [Get exit status of process that's piped to another](http://unix.stackexchange.com/questions/14270/get-exit-status-of-process-thats-piped-to-another) – Stéphane Chazelas Feb 26 '15 at 12:29
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@StéphaneChazelas, the linked question doesn't answer how to chain pipes and && correctly. – anatoly techtonik Feb 26 '15 at 12:56
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See also [How do I get the exit code of cmd1 in cmd1|cmd2](http://unix.stackexchange.com/a/76171) – Stéphane Chazelas Feb 26 '15 at 12:57
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Yes, you're right, the problematic and solutions will be the same, but it's a slightly different question. I've retracted my close vote. – Stéphane Chazelas Feb 26 '15 at 12:58
1 Answers
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The problem is that you'll be checking the exit status of pv. With POSIX sh syntax, you could do:
cd /app && ((make 3>&- && exec sudo nginx -g 'daemon off;' >&3 3>&-) | pv -qL 100) 3>&1
Or with ksh/bash/zsh:
(set -o pipefail
cd /app && make | pv -qL 100 && sudo nginx -g 'daemon off;')
Or with zsh:
cd /app && make | pv -qL 100 && ((!pipestatus[1])) && sudo nginx -g 'daemon off;'
Or with bash:
cd /app && make | pv -qL 100 && ((!PIPESTATUS[0])) && sudo nginx -g 'daemon off;'
Stéphane Chazelas
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Gives me `[STDERR] /bin/sh: 1: !PIPESTATUS[0]: not found`. I run this command with CMD from Dockerfile. – anatoly techtonik Feb 26 '15 at 12:47
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2@techtonik, as I said, `PIPESTATUS` is for `bash`. For `sh`, use the first one. – Stéphane Chazelas Feb 26 '15 at 12:54
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Ended up with `CMD bash -c "(set -o pipefail; cd /app && make | pv -q -L 150 && sudo nginx -g 'daemon off;')"` – anatoly techtonik Feb 26 '15 at 13:21