Why doesn't this tee with process substitution produce the 1st and chosen lines?

Question

What I want is printing the output the first line ( table head ) of ps aux and the grep result.

After search, I come up with following.

ps aux | tee >(head -1 > /dev/tty) | grep mongo

But I find the stdin of grep mongo is cut off.

Also, if I omit > /dev/tty, what will the stdout of head -1 direct to? Why isn't it the console?

(Yes, I know I can achive my purpose by command awk. I am just curious about why my command doesn't work?)

This doesn't appear to be a dupe of the question it was closed as a dupe of. This one is asking why something doesn't work as expected, The other is asking how to accomplish a specific task. — Faheem Mitha, Dec 22 '14 at 15:34
Take a look at [Thor's answer](http://unix.stackexchange.com/a/47922/977) to the other question; he covers why your approach doesn't work, and a way to make it (somewhat) work. (I don't blame you for missing it, it's nowhere near the top. I missed it myself at first, too.) — derobert, Dec 22 '14 at 15:37
Also see a followup asked about that: [How do I use tee to redirect to grep?](http://unix.stackexchange.com/questions/47932/how-do-i-use-tee-to-redirect-to-grep/47934) — derobert, Dec 22 '14 at 15:40
Thanks @derobert the two links solve my question. I think I have more specific keyword to search to understand it. — Sisyphus, Dec 23 '14 at 05:25

score 0 · Answer 1 · answered Dec 22 '14 at 13:54

You could use awk to match two things at the same time:

There you go:

$ ps aux | awk 'NR == 1 || /mongo/ {print $0}'

The NR == 1 condition matches the first line.
The /mongo/ condition matches lines containing "mongo".
{print $0} is the action associated with the two previous conditions, in this case: print the whole line.

1 Answers1