Is this Linux? If so, you could try the following:
# sysctl vm.swappiness=100
(You might want to use sysctl vm.swappiness first to see the default value, on my system it was 10)
And then either use a program(s) that uses lots of RAM or write a small application that just eats up RAM. The following will do that (source: Experiments and fun with the Linux disk cache):
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <unistd.h>
int main(int argc, char** argv) {
int max = -1;
int mb = 0;
int multiplier = 1; // allocate 1 MB every time unit. Increase this to e.g.100 to allocate 100 MB every time unit.
char* buffer;
if(argc > 1)
max = atoi(argv[1]);
while((buffer=malloc(multiplier * 1024*1024)) != NULL && mb != max) {
memset(buffer, 1, multiplier * 1024*1024);
mb++;
printf("Allocated %d MB\n", multiplier * mb);
sleep(1); // time unit: 1 second
}
return 0;
}
Coded the memset line to initialise blocks with 1s rather than 0s,
because the Linux virtual memory manager may be smart enough
not to actually allocate any RAM otherwise.
I added the sleep(1) in order to give you more time to watch the processes as it gobbles up ram and swap. The OOM killer should kill this once you are out of RAM and SWAP to give to the program. You can compile it with
gcc filename.c -o memeater
where filename.c is the file you save the above program in. Then you can run it with ./memeater.
I wouldn't do this on a production machine.
